Abcd Is A Trapezium With Ab Parallel To Dc And Triangle Aed Is Similar To Triangle Bec
In Fig Abcd Is A Trapezium With Ab Parallel To Dc If Triangle ођ If a e d is similar to b e c. prove that ad=bc. q. figure shows the electric lines of force emerging from a charged body. if the electric field at a and b are e a and e b respectively and if the displacement between a and b is r then. Abcd is a trapezium with ab parallel to dc and triangle aed is similar to triangle bec. prove that ad = bcthis video is about.
In The Figure Abcd Is A Trapezium In Which Ab Parallel To Dc Diagonals Click here:point up 2:to get an answer to your question :writing hand:in given figure abcd is a trapezium with abdc if. Abcd is a trapezium with ab∥cd. if ∆aed is similar to ∆bec, prove that ad=bc.class 10important problem cbsetelangana and andhra pradesh state syllabus @khaja. In figure, abcd is a trapezium with ab||dc, if aed is similar to bec, prove that ad = bc. view solution. q4. The picture support the above solution. on the other hand ot is possible to go another way. trinagles amo and acd are similar. then $\frac{mo}{dc}=\frac{ao}{ac}$.
Ex 6 2 9 Abcd Is A Trapezium In Which Ab Dc And Ex 6 2 In figure, abcd is a trapezium with ab||dc, if aed is similar to bec, prove that ad = bc. view solution. q4. The picture support the above solution. on the other hand ot is possible to go another way. trinagles amo and acd are similar. then $\frac{mo}{dc}=\frac{ao}{ac}$. Also, i am not sure where to start with showing the diagonals of a trapezoid cut each other into segments that are proportional to the parallel sides of the trapezoid. here is what i have gotten so far $\textbf{attempt:}$ if two triangle are similar than it follows that one triangle must be a scaler of the other triangle. If two parallel lines are cut by a transversal, then alternate interior angles are congruent. thus, $\angle abp \cong \angle cdp$ and $\angle cab \cong \angle dcp$. therefore, $\triangle abp \sim \triangle cdp$. we are also given that the area of $\triangle abp$ is $32~\text{cm}^2$, while the area of $\triangle cdp$ is $50~\text{cm}$.
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