Solved A Particle Moves According To A Law Of Motion S Chegg
Solved A Particle Moves According To A Law Of Motion S Chegg Step 1. a particle moves according to a law of motion s = f ( t), t ≥ 0, where t is measured in seconds and s in feet. f ( t) = 0.01 t 4 − 0.02 t 3. view the full answer step 2. Calculus. calculus questions and answers. a particle moves according to a law of motion s = f (t), t >= 0, where t is measured in seconds and s in feet.f (t) = t3 − 12t2 36t (a) find the velocity at time t.v (t) = (b) what is the velocity after 4 s?v (4) = ft s (c) when is the particle at rest? (enter.
Solved A Particle Moves According To A Law Of Motion Chegg A particle moves according to a law of motion s = f (t), t >= 0, where t is measured in seconds and s in feet.f (t) = 0.01t4 − 0.02t3 (a)find the velocity at time t (in ft s).v (t) = (b)what is the velocity (in ft s) after 1 s?v (1) = ft s (c)when (in seconds) is the particle at rest? (smaller value) t. The particle moves in a positive direction when the velocity is positive. so solve: 3t 2 − 18t 24 > 0. t 2 − 6t 8 > 0 (t 2)(t 4) > 0. solution 1: t > 0 but t < 2 or [0, 2) solution 2: t > 4 or (4, ∞) e) draw a diagram to illustrate the motion of the particle and use it to find the total distance (in ft) traveled during the first 6. A particle moves according to a law of motion s = f(t), t ≥ 0, where t is measured in seconds and s in feet. f(t) = 0.01t4 − 0.06t3 1) when is the particle moving in the positive direction? (enter your answer using interval notation.) 2)find the total distance traveled during the first 9 seconds. A particle moves according to a law of motion s= f(t), t≥0, where tis measured in seconds and sin feet. (a)find the velocity at time t. (b)what is the velocity after 1 second? (c)when is the particle at rest? (d)when is the particle moving in the positive direction? (e)find the total distance traveled during the first 6 seconds.
Solved A Particle Moves According To A Law Of Motion S Chegg A particle moves according to a law of motion s = f(t), t ≥ 0, where t is measured in seconds and s in feet. f(t) = 0.01t4 − 0.06t3 1) when is the particle moving in the positive direction? (enter your answer using interval notation.) 2)find the total distance traveled during the first 9 seconds. A particle moves according to a law of motion s= f(t), t≥0, where tis measured in seconds and sin feet. (a)find the velocity at time t. (b)what is the velocity after 1 second? (c)when is the particle at rest? (d)when is the particle moving in the positive direction? (e)find the total distance traveled during the first 6 seconds. In interval notation, the particle moves in a positive direction from t=5.5 until the end of time (infinity) but at t=5.5 it is not positive nor negative, it is 0. so with interval notation, both endpoints will be curved because the end point t=5.5 is not included nor is the end point of infinity inifinity is never included because "t" never. Edit: if you don't know the arc length formula another approach to calculate the traveled distance of a particle satisfying a law of motion s(t) s ( t) between t = a t = a and t = b t = b would be to calculate the critical points in (a, b) ( a, b), say t1 < ⋯ <tk t 1 < ⋯ < t k, and then calculate the traveled distance as |s(t1) − s(a.
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