Solved Tickets From Lottery A Contain 6 Different Numbers Chegg Question: tickets from lottery a contain 6 different numbers between 1 and 52 and the order of the numbers does not matter. how many different tickets are possible? tickets from lottery b contain 6 different numbers between 1 and 45 and the order of the numbers does not matter. how many different tickets are possible? which lottery is easier to. Answer to solved a lottery ticket contains six different numbers, | chegg.
Solved A Lottery Ticket Is 4 A Ticket Having 6 Chegg See answer. question: 5. a lottery ticket contains six different numbers, chosen from 1 to 39. the winning ticket will match all six numbers in the correct order, plus a bonus number, which may match the other six numbers. the second prize matches the six winning numbers in the correct order, but not the bonus number. A lottery ticket contains six different numbers, chosen from 1 to 39. the winning ticket will match all six numbers in the correct order, plus a bonus number, which may match the other six numbers. the second prize matches the six winning numbers in the correct order, but not the bonus number. what is the probability of winning first or second. Then you choose the next correct number. the probability is $\frac5{48}$ and so on. then the probability of choosing an incorrect number if 4 correct numbers have been choosen is $\frac{49 6}{49 4}=\frac{43}{45}$ similar for the next incorrect number. and finally you have to count the ways of choosing 2 incorrect and 4 correct numbers. In lottery a, there are 20,358,520 different tickets possible, while in lottery b, there are 8,145,060 different tickets possible.lottery b is easier to win. in lottery a, there are 6 different numbers between 1 and 52, and the order of the numbers does not matter.
Solved A Lottery Ticket Is 4 A Ticket Having 6 Chegg Then you choose the next correct number. the probability is $\frac5{48}$ and so on. then the probability of choosing an incorrect number if 4 correct numbers have been choosen is $\frac{49 6}{49 4}=\frac{43}{45}$ similar for the next incorrect number. and finally you have to count the ways of choosing 2 incorrect and 4 correct numbers. In lottery a, there are 20,358,520 different tickets possible, while in lottery b, there are 8,145,060 different tickets possible.lottery b is easier to win. in lottery a, there are 6 different numbers between 1 and 52, and the order of the numbers does not matter. Watch how to calculate the probability of winning a lottery using permutations and combinations. learn from khan academy's free math videos and exercises. Tickets from lottery a contain 6 different numbers between 1 and 53 and the order of the numbers does not matter. how many different tickets are possible? tickets tickets from lottery b contain 6 different numbers between 1 and 47 and the order of the numbers does not matter.
Comments are closed.