Ultimate Solution Hub

The Greatest Number Of Four Digits Which Is Exactly Divisible By

Find the Greatest number of Four digit which Is Exactly divisibleођ
Find the Greatest number of Four digit which Is Exactly divisibleођ

Find The Greatest Number Of Four Digit Which Is Exactly Divisibleођ The greatest number of times 3 occurs in the numbers (15, 24, 36) : two; lcm =2∗2∗2∗3∗3=72; 2. to find the greatest four digit number divisible by 72: the greatest four digit number is 9999; 9999 when divided by 72 is 138.875 ( 138.875 is not an integer, thus 9999 is not divisible by 72. ) the greatest four digit number divided by. Solution. verified by toppr. the greatest four digit number = 9999. we can get the required number by following steps: step 1 : divide 9999 by lcm of 15, 24 and 36. step 2 : subtract result of step 1 from 9999. prime factorization : 15 = 3 × 5. 24 = 2 3 × 3.

Find the Greatest Number Of Four Digits Which Is Exactly Divisible By
Find the Greatest Number Of Four Digits Which Is Exactly Divisible By

Find The Greatest Number Of Four Digits Which Is Exactly Divisible By The greatest number of four digits which is divisible by 15, 25, 40 and 75 is9400900096009800. solve. "find the largest $4$ digit number that is exactly divisible by $12,15,18$ and $27$." if all those number divide into that 4 digit number than that 4 digit number is a multiple of all those numbers. so the 4 digit number is a common multiple of all of those. "the solution is by finding out the lcm of these numbers. i mean why ?". To find out a number that is divisible by 8, 12, 15 a n d 20 we need to find the lcm of these numbers. l.c.m of 8, 12, 15, 20 = 120 also, we know that greatest 4 digits number is 9999. The number is exactly divisible by 540 hence 9720 is the largest 4 digit number divisible by 12, 15, 18 and 27. note: lcm of given numbers is exactly divisible by each of the numbers. during the lcm calculation, students must know the tables of various numbers, and they have to perform the operations step by step.

Find the Greatest number of Four digits exactly divisible By 8 1
Find the Greatest number of Four digits exactly divisible By 8 1

Find The Greatest Number Of Four Digits Exactly Divisible By 8 1 To find out a number that is divisible by 8, 12, 15 a n d 20 we need to find the lcm of these numbers. l.c.m of 8, 12, 15, 20 = 120 also, we know that greatest 4 digits number is 9999. The number is exactly divisible by 540 hence 9720 is the largest 4 digit number divisible by 12, 15, 18 and 27. note: lcm of given numbers is exactly divisible by each of the numbers. during the lcm calculation, students must know the tables of various numbers, and they have to perform the operations step by step. The concept of lcm is the multiple of least common multiple. calculations: ⇒ lcm of 15, 24, and 40 = 120. ⇒ highest 4 digit number = 9999. on dividing 9999 by 120, we get. ⇒ remainder = 39. ⇒ the highest 4 digit number divisible be 15, 24, and 40 = highest 4 digit number remainder = 9999 39 = 9960. ⇒ hence, the highest 4 digit. 9999 = = (27 × × 360) 279. now, clearly, when 9999 is divided by 360, we are left with the remainder 279. hence, we will subtract this remainder from 9999. thus, we get, 9999 − 279 = 9720 9999 − 279 = 9720. therefore, the greatest number of four digits which is exactly divisible by 15,24 and 36 is 9720.

Comments are closed.