How To Check Whether A Given Number Is A Perfect Square Or Not In C This video is to check whether the given number is a perfect square or not which is an important c interview question. this program is done using simple logi. Visit to find more such videos channel uc 8xvxifssq2ediqyc1skjqinstructor ishan kesarwani.
To Check The Number Is Perfect Square Or Not In C Program 13 Youtube In this video, we will write a c program to check whether a number is a perfect square or not. basically, a perfect square is a result of multiplying by itself and a number formed i.e perfect square = n*n. examples: input: n = 25 output: yes, it is a perfect square. input: n = 64 output: yes, it is a perfect square. we will be using two. First of all get the square root of the given number and assign this float value into an integer variable, then only integer part of the number will be stored in integer variable after that compare integer and float variables if their values are same it means number is perfect square, because perfect square number's square root does not has. Simple c program to check if the user input number is a perfect square or not in c language with stepwise explanation. 朗 new cool developer tools for you. explore →. For every iteration of i, number == i*i will check if the square of i is matching with number. if it matches then the number has a perfect square and we will make the flag=1. if no i value satisfies the perfect square condition, then flag value remains 0. at the end of the program if the flag=0, then the given number is not a perfect square.
C Program To Check Whether A Number Is Perfect Square Or Not Simple c program to check if the user input number is a perfect square or not in c language with stepwise explanation. 朗 new cool developer tools for you. explore →. For every iteration of i, number == i*i will check if the square of i is matching with number. if it matches then the number has a perfect square and we will make the flag=1. if no i value satisfies the perfect square condition, then flag value remains 0. at the end of the program if the flag=0, then the given number is not a perfect square. Check if a given number n is a perfect square or not. if yes then return the number of which it is a perfect square, else print 1. examples: input: n = 4900 output 70 explanation: 4900 is a perfect square number of 70 because 70 * 70 = 4900 input: n = 81 output: 9 explanation: 81 is a perfect square number of 9 because 9 * 9 = 81 approach: to solv. Scanf("%d", &n); note however that your function will print both success and fail for perfect squares because you should return from the function instead of just breaking from the loop upon success. here is a modified version: #include <stdio.h>. void isperfectsquare(int number) {. int i;.
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